主题：【分享】常用英文化学分子式、方程式及数学式的读法

如果看不清楚，请下载附件
常用英文化学分子式、方程式及数学式的读法

Na2SO4 Sodium sulphate; C-a-two-S-O-four
Mg(OH)2 magnesium hydroxide; M-g-pause-O-H-pause-twice; M-g-in brackets twice
Ca2(PO4)3· 2H2O calcium phosphate two hydrate; C-a-two-pause-P-O four-pause- three times-dot-two-H two-O
[Zn(NH3)4]2+ tetra-ammonium zinc complex cation
? give; yield; produce, form,become
- evolved as a gas; give off a gas
ˉ is precipitated; gives X precipitate
= reacts reversibly


--------------------------------------------------------------------------------
Cu, D in the precence of a copper as a catalyst on heating
CO32- + Ca2+ = CaCO3ˉ a carbonate anion with a valancy of two plus a calcium cation with a valancy of two produce a calcium carbonate precipitate
R’ R prime
R” R double prime, R second prime
R1 R sub one
100° C one hundred degrees Centigrade
+ plus; positive
- minus; negative
′ multiplied by; times
? divided by
± plus or minus
= is equal to; equals
o is identically equal to
? is approximately equal to
( ) round brackets; parentheses
[ ] square brackets
{ } braces
a>>b a is much greater than b
a3 b a is greater than or equal to b
aμ b a varies directly as b
lognX logX to the base n
the cubic root of x
the nth root of x
x2 x square, x squared, the square of x
Xn X to n factors; the nth power of x; x to the power n
x -8 x to the minus eighth power
? x? the absolute value of x
the mean value of X
the sum of the terms indicated; summation of
D x or d x the increment of x
dx differential x
dy/dx the first derivative of y with respect to x
ò integral
￥ infinity
1/2 a half; one half
2/3 two thirds
5/123 five over a hundred and twenty-three
eight and three over fourths; eight and three quarters
0.01 O point O one; zero point zero one; nought point nought one
6 % 6 percent
3‰ 3 per mille
2 : 3 the ratio of two to three
r=xd r equals x multiplied by d
5′ 2=10 five times two equals ten
x3/8=y2 x raised to the third power divided by eight equals y squared
(a+b-c′ d)/e=f a plus b minus c multiplied by d, all divided by e equals f
y = (Wt-W)/x y equals W sub t minus W over x 


一