主题:【讨论】旋转蒸发器和循环水冷却器

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ghcily
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各位版友,讨论一个问题
假如我要给旋转蒸发器配备循环水冷却器,怎么计算需要多大制冷量的循环水冷却器?就是说有没有简单的计算方法?
比如:旋蒸是5L的,加热温度是50度,希望冷凝管的温度是10度,怎么计算得出需要的循环水冷却器的制冷功率是多大的?
希望有这方面经验的高手帮忙解答一下。
推荐答案:lzutrunks回复于2010/07/30
除了考虑蒸发瓶的体积,加热温度和冷凝管温度外,还需要分别考虑是哪一种溶剂在被蒸发
然后根据溶剂本身的蒸发热进行计算
Q = flow rate x heat of vaporization x density
Q = heat load in Watt
flow rate: in ml/hour
heat of vaporization: in Kcal/g
density: in g/ml
Example
Collecting 300 ml of methylene chloride in 30 minutes
1. Convert volume to weight: 300 ml x density of 1.33 g/ml = 399 g
2. Convert minutes to hours: 399 g in 30 min = 798 g/hr
3. Multiply by the latent heat of vaporization: 798 g/hr x 89 cal/g = 71022 cal/hr
4. Divide by 1000 to get Kcal: 71022 / 1.000 = 71,022 kcal/hr
5. Multiply by 1.16 to get Watts: 71,022 x 1.16 = 82 Watt
Add a security factor of at least 20% for loss of cooling capacity due to high
ambient, long tubing, etc.: 82 x 1.2 = 98 Watt

举个例子,我们在计算的时候基本按照这个方法来做
为了保证可操作性,一般在计算所得数据上再乘1.1到1.2的系数,就万无一失了
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ghcily
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雾非雾
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我们买的循环水冷却器是厂家与旋转蒸发器配套的,我们的冷却水控制在3度,在实际用的过程中发现这个循环水冷却器至少可以带3-4台旋转蒸发器的。
lzutrunks
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除了考虑蒸发瓶的体积,加热温度和冷凝管温度外,还需要分别考虑是哪一种溶剂在被蒸发
然后根据溶剂本身的蒸发热进行计算
Q = flow rate x heat of vaporization x density
Q = heat load in Watt
flow rate: in ml/hour
heat of vaporization: in Kcal/g
density: in g/ml
Example
Collecting 300 ml of methylene chloride in 30 minutes
1. Convert volume to weight: 300 ml x density of 1.33 g/ml = 399 g
2. Convert minutes to hours: 399 g in 30 min = 798 g/hr
3. Multiply by the latent heat of vaporization: 798 g/hr x 89 cal/g = 71022 cal/hr
4. Divide by 1000 to get Kcal: 71022 / 1.000 = 71,022 kcal/hr
5. Multiply by 1.16 to get Watts: 71,022 x 1.16 = 82 Watt
Add a security factor of at least 20% for loss of cooling capacity due to high
ambient, long tubing, etc.: 82 x 1.2 = 98 Watt

举个例子,我们在计算的时候基本按照这个方法来做
为了保证可操作性,一般在计算所得数据上再乘1.1到1.2的系数,就万无一失了
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2010/7/30 16:29:50 Last edit by lzutrunks
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