原文由 longchina(longchina) 发表:
Thank you for contacting the application support hotline. The DSC measurement goes into two very simple relationships.
1 watt = 1 amp (current) * 1 volt
In a DSC, a very stable current source is used, thereby keeping current as a fixed parameter throughout the DSC experiment. From the above equation one can then calculate the total watts. The Watt is then divided by the total sample size entered into the software.
When you integrate an area, the area is integrated on a time scale using the relationship of 1Watt = 1Joule/second.
还是不很清楚到底应该是如何去计算的。
原文由 大陆(handsomeland) 发表:原文由 tutm(tutm) 发表:
这个公式中没有发现V和W的关系啊?
原文由 longchina(longchina) 发表:原文由 longchina(longchina) 发表:
Thank you for contacting the application support hotline. The DSC measurement goes into two very simple relationships.
1 watt = 1 amp (current) * 1 volt
In a DSC, a very stable current source is used, thereby keeping current as a fixed parameter throughout the DSC experiment. From the above equation one can then calculate the total watts. The Watt is then divided by the total sample size entered into the software.
When you integrate an area, the area is integrated on a time scale using the relationship of 1Watt = 1Joule/second.
还是不很清楚到底应该是如何去计算的。
其实这个鬼子就是TA的support,但我觉得他就没解释清楚,耍了个花枪。而且电压信号已经代表了温度,或者热流的功率值了,再去考虑物质的比热,和质量,好像就多余了。
原文由 tutm(tutm) 发表:原文由 longchina(longchina) 发表:
其实这个鬼子就是TA的support,但我觉得他就没解释清楚,耍了个花枪。而且电压信号已经代表了温度,或者热流的功率值了,再去考虑物质的比热,和质量,好像就多余了。
从简单直观的物理层面上理解,这里的电压信号仅直接反映了样品与参比的温度差,而与热流功率有一定的关系。但问题是电压与热流功率究竟是什么关系呢?这就是你原先的问题呀。
这个关系转换,我认为一定不是按简单物理原理进行电功率计算,而一定与标样有关,包括它的比热(或热焓)、质量等。
你咨询的那位TA老外,把竞争对手PE完全不同的方法拿来解释自己原理大相径庭的仪器,真会“捣浆糊”。
可能我写的东西表达水平不行,思路有点跳跃,让各位费神了。